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![If 'a' the length of side of the cube, the distance between the body-centred atom and one corner atom in the cube will be:[A] $\\dfrac{4}{\\sqrt{3}}a$ [B] $\\dfrac{\\sqrt{3}}{4}a$ [C] $\\dfrac{\\sqrt{3}}{2}a$[D] $\\dfrac{2}{\\sqrt{3}}a$](https://www.vedantu.com/question-sets/720721fd-3ab5-4f3a-8864-68a0dfdd06901210945075913440462.png "If 'a' the length of side of the cube, the distance between the body-centred atom and one corner atom in the cube will be:[A] $\\dfrac{4}{\\sqrt{3}}a$ [B] $\\dfrac{\\sqrt{3}}{4}a$ [C] $\\dfrac{\\sqrt{3}}{2}a$[D] $\\dfrac{2}{\\sqrt{3}}a$")
If 'a' the length of side of the cube, the distance between the body-centred atom and one corner atom in the cube will be:[A] $\\dfrac{4}{\\sqrt{3}}a$ [B] $\\dfrac{\\sqrt{3}}{4}a$ [C] $\\dfrac{\\sqrt{3}}{2}a$[D] $\\dfrac{2}{\\sqrt{3}}a$
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In the above figure, calculate the length of the body diagonal, if the length of each edge of the cube is $\\dfrac{1}{2}$ inch.\n \n \n \n \n A. $\\dfrac{1}{6}$B. $\\dfrac{1}{4}$C. $\\dfrac{{\\sqrt 3 }}{
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there is a cubic frame on each corner a pont massm are kept tell about momet of inertia if axis is pass through body diagonal of cubeeach side of cube 1u06l1vv -Physics -
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AB = diagonal (axis) moment of inertia of all the edges of cube
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